Calculate the power of a the lift motor

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itouch

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please help dont know ans

Question:

Calculate the power of a the lift motor,when is lift on a distance on a building site lift 400kg of brick 50m to the top of a buiding in 24 seconds

Thanks

 
We'll all try and help, but first let us know if you can think of any formulae that you can use.

 
Hello itouch, as Ali says can you think of any relevant formula, obviously this power calculation is nothing to do with volts x current. You probably need to be thinking about work done and how long it takes to do the work. You should have covered something similar in your course work.

Doc H.

 
this is how I would do it; Could be wrong and often I am!!!

Power = Energy/Time.

Energy(J)= Load x 9.81 x Vertical Distance.

So: 400 x 9.81 x 50 = 196200 joules, There for 196200/24 = 8175 Watts

BTW (9.81 is for Working out Joules)

 
you need to add the lift weight and frictional force in order to calculate the power for lift motor

 
Weight is 882Lbs

Height is 164.04 feet

Time is 24 seconds

One horsepower is 33,000 ft/lb in a minute

One minute is 60 seconds. 60/24 = 2.5

So, 882lbs x 164.04 feet x 2.5 = 361708.2

All divided by 33000 = 10.960 hp required

[so much for "modern" mumbo jumbo metric rubbish.....]

[plus an allowance for frictional losses and accellerating the load]

john...

 
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