Revision - Transformers

Hi guys.

I'm revising for an exam and we haven't really done anything about transformers since before xmas. Can someone please check if I have done this calculation right?

"A transformer has 50 turns on the primary and 8 turns on the secondary. The primary is supplied at 600V. The output on the secondary will be...?"

Am i right in thinking it's (voltage of winding / number of turns) * amount of turns on the secondary? So (600/50)*8 = 96. So the output would be 96V?

If I'm wrong please tell me and I'll try to work it out. Thank you

Correct...  you just need to remember that....

Voltage Primary/Voltage Secondary = No Of Turns Primary/No Of Turns Secondary = Current Secondary/Current Primary..

So whatever values you are given use and transpose the bits accordingly..

BUT don't forget that the current ratio is arse about face to the others.. i.e  Secondaryrimary  not Primary:Secondary.

Bottom line is (excluding small losses) the transformer does not generate or consume any power,

so if the Voltage goes down.. the current must go up.. so V*I remains equal on both sides..

(thats why need care with conductor sizes on low voltage lighting as 50W @ 230V  = 0.2A ish  

but 50W @ 12v = 4A ish)

Guinness

+1.

As I drive about I am amazed at the long term reliability of these beasts.

Some have been in continuous service for at least 50 years within the

distribution network.

Thank you very much SL. Scoobed for that answer

The way I try remember it that you always have to divide the bigger number by the smaller number.