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amateursparky

help with questions on 2391

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amateursparky

for q26 i dont get how i can work out the answer without r1 and rn end to end values

2391 q2.png

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SPECIAL LOCATION

You are given the length of the ring...

 

and from tables in the OSG you can work out the resistances per meter is for most common CSA's...

 

:Salute  

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amateursparky

sorry can you someon spoon feed me a little. were in the osg am i looking? i feel out of my depth here.

 

 

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Doc Hudson
22 minutes ago, amateursparky said:

sorry can you someon spoon feed me a little. were in the osg am i looking? i feel out of my depth here.

 

 

 

I do hope you are not out of your depth with something so basic?  The contents start on page 3 and go thro to page 5 of the OSG, if you cannot work out which section(s) you may or may not need to calculate the expected resistance of a cable with a given length and CSA, then really you should not be attempting any exams yet. May be good to contact your tutor if they have missed this out of your course content?

 

Doc H.

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amateursparky

sorry. found it now.

Panic is setting in. I have failed my practical because i rushed it.

I knew how to do all the things iI missed and my tuor knews it but she had to fail me because be unfair on others.

She will also be doin a diservice to the industry if she passed me.

 

 I will be trying to find someone i can train under before setting out on my own. It's not easy being 33.

The goverment favours lads who are more interested in getting laid then laying cables(pun intended)/getting smashed at the bar than laying cables.

 

In 30 years time perhaps i will be having this conversion with someone else.

Edited by amateursparky

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kerching

So,what did you get for your answer?

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