Quick easy question

Talk Electrician Forum

Help Support Talk Electrician Forum:

This site may earn a commission from merchant affiliate links, including eBay, Amazon, and others.

kiwiNCFC

Senior Member
Joined
Apr 19, 2009
Messages
155
Reaction score
0
i was reading my 2330 lvl 2 book and it says in there:

for lighting outlets we should assume a

current equivalent to a minimum of 100 W per lampholder. This means that

for a domestic lighting circuit rated at 5 A, a maximum of 11 lighting outlets

could be connected to each circuit

How does the author get 11?

Thanks

EDIT: just had a thought, is it like this: 100X11 = 1100 / 230 = 4.7 meaning a 5amp fuse/mcb would do?

 
i was reading my 2330 lvl 2 book and it says in there:for lighting outlets we should assume a

current equivalent to a minimum of 100 W per lampholder. This means that

for a domestic lighting circuit rated at 5 A, a maximum of 11 lighting outlets

could be connected to each circuit

How does the author get 11?

Thanks

EDIT: just had a thought, is it like this: 100X11 = 1100 / 230 = 4.7 meaning a 5amp fuse/mcb would do?
Correct. :) (On a re-wireable=5A. on a BS60898=6A)

 
i was reading my 2330 lvl 2 book and it says in there:for lighting outlets we should assume a

current equivalent to a minimum of 100 W per lampholder. This means that

for a domestic lighting circuit rated at 5 A, a maximum of 11 lighting outlets

could be connected to each circuit

How does the author get 11?

Thanks

EDIT: just had a thought, is it like this: 100X11 = 1100 / 230 = 4.7 meaning a 5amp fuse/mcb would do?
So quick a quiestion...

You answered it correctly yourself m8!!!

:^OApplaud SmileyApplaud SmileyApplaud Smiley

But spose it is still good to confirm you ARE thinking on the right lines! ;)

Guiness Drink

 
Top