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Do-It-Yourself (DIY) Question & Answer Forum
Actual Power Requirement
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<blockquote data-quote="David B" data-source="post: 515094" data-attributes="member: 33930"><p>Many thanks - pure sine wave certainly also double the wattage - good advice.</p><p></p><p>My quandary is that following Ohms Law V x A =W the wattage of my battery charger should be 268.8 but the shown value according to my power meter show 161w. Clearly if this is multiplied by the Power Factor of 0.6 = 161w is correct. So, should I base my requirement on double 161w or double 268w?</p><p></p><p>P.S. The figure I quoted were what my power meter was showing while charging the battery so actual figures.</p></blockquote><p></p>
[QUOTE="David B, post: 515094, member: 33930"] Many thanks - pure sine wave certainly also double the wattage - good advice. My quandary is that following Ohms Law V x A =W the wattage of my battery charger should be 268.8 but the shown value according to my power meter show 161w. Clearly if this is multiplied by the Power Factor of 0.6 = 161w is correct. So, should I base my requirement on double 161w or double 268w? P.S. The figure I quoted were what my power meter was showing while charging the battery so actual figures. [/QUOTE]
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