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Intruder, Fire, CCTV, Emg Light, Access Control
External Alarm Bell
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<blockquote data-quote="brian_mk" data-source="post: 485241" data-attributes="member: 31693"><p>You may be right, but I'm a retired engineer, so I like trying to fix things (as long as it doesn't involve climbing ladders). <img class="smilie smilie--emoji" loading="lazy" alt="🙂" title="Slightly smiling face :slight_smile:" src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f642.png" data-shortname=":slight_smile:" /></p><p></p><p>It seems odd to me that the control panel gives no warning that the tamper loop has failed (i.e. is already open circuit when the alarm is initially enabled).</p><p></p><p>That seems like bad design. I would have expected a warning LED to be illuminated or for the alarm to trigger in this situation.</p><p></p><p>I'm guessing the tamper alarm must be edge triggered rather than level triggered.</p><p></p><p>If you disconnect the tamper loop and replace it with a test switch, the alarm does trigger when the switch is opened.</p><p></p><p>The tamper arrangement appears to operate differently to the alarm circuit.</p><p></p><p>If the alarm loop is already open circuit when the alarm is first enabled, a LED is illuminated and the alarm sounds.</p></blockquote><p></p>
[QUOTE="brian_mk, post: 485241, member: 31693"] You may be right, but I'm a retired engineer, so I like trying to fix things (as long as it doesn't involve climbing ladders). 🙂 It seems odd to me that the control panel gives no warning that the tamper loop has failed (i.e. is already open circuit when the alarm is initially enabled). That seems like bad design. I would have expected a warning LED to be illuminated or for the alarm to trigger in this situation. I'm guessing the tamper alarm must be edge triggered rather than level triggered. If you disconnect the tamper loop and replace it with a test switch, the alarm does trigger when the switch is opened. The tamper arrangement appears to operate differently to the alarm circuit. If the alarm loop is already open circuit when the alarm is first enabled, a LED is illuminated and the alarm sounds. [/QUOTE]
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