Energy Dissipated

Talk Electrician Forum

Help Support Talk Electrician Forum:

This site may earn a commission from merchant affiliate links, including eBay, Amazon, and others.

skystorm

Member
Joined
Jun 27, 2009
Messages
53
Reaction score
0
Location
Scotland
Hi all

Here is one, A current of 4.5A flows in a 3.5ohms resister for 5.5 minutes. The energy dissipated is ,

can anyone refesh this old mind of my and show how its done thanks

 
4.5 x 3.5 x 330 =2,450,12 missed the squared out , if i do it with the square in i get syntax error

 
You must be pressing wrong sequence on calculator mate. Do 4.5 squared first by doing 4.5 x 4.5 then press equals then do rest of sum. :)

 
well whaddya know,

never ever seen a calculator returning a syntax error before.!!! :C

you sure you have 2391?

we werent even allowed scientific calculators when I done mine.

 
well whaddya know,never ever seen a calculator returning a syntax error before.!!! :C

you sure you have 2391?

we werent even allowed scientific calculators when I done mine.
Thats cuz they weren't invented!!!!!!

Slide-rule...

Pencil...

& back-o-the-fag-packet you told Deke????

 
Hi All,

I will do it the "pen and paper way" or just using the extremely basic calculator on my PC and my not very up to speed brain!!!

Right, so we have a resistor of 3.5 ohms and a current of 4.5 Amps..

So, current times resistance gives voltage, so 3.5 ohms x 4.5 Amps = 15.75 Volts..

Now, Volts times current gives Watts.. So, 15.75 Volts x 4.5 Amps = 70.875 Watts.

Now, this "power", i suppose is the best term, [the 70 odd watts] is flowing for 5.5 minutes.

5.5 minutes is obviously 5.5 x 60 seconds = 330 seconds

A Watt flowing for one second = one Joule...

So if we multiply our 70.875 Watts by 330 seconds, we come up with 23388.75 Joules which is the answer!!

So, energy dissipated... 23388.75 Joules

john..

 

Latest posts

Top